`weekiat*
`geraldine*
`huixian*
`virginia*
`erina*
'royston*
`benjamin*
`jasmine*
`jenny jie*
`val jiejie*
`tiffany*
`melody*
`iris*
`rachel*
'yuen leng*
'geraldine11*
'joel*
'sherry*
'terry*
`huikoon*
`tasneem*
`jocelyn*
`khinewa*
`sherman*
`sheryl*
`thiamkee*
`justin*
`bernard*
`kevin.caleb*
`tingzhang*
`inez*
`xiangting*
`luther*
`genevis*

probability of me failing the probability test is quite high.

but i wish...

Binomial Distribution
n = no of trials = 1 ( better be 1...)
p = probability of success = 0.8 ( THIS is being super optimistic)..

but.. i think FOR NOW, is p = 0.5

see this..
michelle did a probability test. there is 5 qns in the test. the probability of locals being able to do prof HMM's qns is 0.3. what is the probability of michelle getting ONLY 2 qns correct?

X~B(5,0.3)

the DESIRED probability= P(X=2)
= (5C2) (0.3)^2 (0.7)^3
= 0.3087 <---- OMG!!!!!

let's be optimistic again...

X~B(5,0.6)

the DESIRED probability= P(X=2)
= (5C2) (0.6)^2 (0.4)^3
= 0.2304 <---- better?

how about this?
there is 5 qns in the test. the probability of locals being able to do prof HMM's qns is 0.3.
what is the probability of michelle getting at least 2 qns correct?

P(X>=2) = ** i use the binomial table... wait arh let me see..**
= 0.4718 <--- whey, not even HALF leh

let's be optimistic again...

X~B(5,0.6)

P(X>=2) = ** use the binomial table again...**
= ~ 0.87 <--- WOOHOO!

feeling super high now...
do u guys feel the high-ness with me?

i am going crazy.

`scribbled at-
Saturday, September 29, 2007